What is the inverse of f(x)= 1/5 x^3-3 ?

The inverse of f(x)= 1/5 x^3-3 is cube root of 5x+15

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inverse of f(x)= 1/5 x^3-3

inverse

f (x) = \frac{1}{5} x^{3} - 3

Solution steps

y = \frac{1}{5} x^{3} - 3

Replace

x

with

y

x = \frac{1}{5} y^{3} - 3

Solve for

y, x = \frac{1}{5} y^{3} - 3

f (x) = - 2 x

\frac{3 x ^{2}}{x ^{2} - 4}

- \frac{2}{7} cos (\frac{7}{6} x)

sin (2 π t)

f (x) = 3 x - 1

What is the inverse of f(x)= 1/5 x^3-3 ?
The inverse of f(x)= 1/5 x^3-3 is cube root of 5x+15