What is the inverse of f(x)=log_{2}(x)-log_{2}(12) ?

The inverse of f(x)=log_{2}(x)-log_{2}(12) is 3*2^{2+x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=log_{2}(x)-log_{2}(12)

inverse

f (x) = lo g_{2} (x) - lo g_{2} (12)

3 \cdot 2^{2 + x}

Solution steps

y = lo g_{2} (x) - lo g_{2} (12)

Replace

x

with

y

x = lo g_{2} (y) - lo g_{2} (12)

Solve for

y, x = lo g_{2} (y) - lo g_{2} (12)

3 \cdot 2^{2 + x}

What is the inverse of f(x)=log_{2}(x)-log_{2}(12) ?
The inverse of f(x)=log_{2}(x)-log_{2}(12) is 3*2^{2+x}