What is the inverse of x/(sqrt(x^2-9)) ?

The inverse of x/(sqrt(x^2-9)) is (3xsqrt(x^2-1))/(x^2-1),-(3xsqrt(x^2-1))/(x^2-1)

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inverse of x/(sqrt(x^2-9))

inverse

\frac{x}{x ^{2} - 9}

\frac{3 x x ^{2} - 1}{x ^{2} - 1}, - \frac{3 x x ^{2} - 1}{x ^{2} - 1}

Solution steps

y = \frac{x}{x ^{2} - 9}

Replace

x

with

y

x = \frac{y}{y ^{2} - 9}

Solve for

y, x = \frac{y}{y ^{2} - 9}

\frac{3 x x ^{2} - 1}{x ^{2} - 1}, - \frac{3 x x ^{2} - 1}{x ^{2} - 1}

What is the inverse of x/(sqrt(x^2-9)) ?
The inverse of x/(sqrt(x^2-9)) is (3xsqrt(x^2-1))/(x^2-1),-(3xsqrt(x^2-1))/(x^2-1)