What is the domain of (4x-8)/((x-4)(x+1)) ?

The domain of (4x-8)/((x-4)(x+1)) is x 4

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domain of (4x-8)/((x-4)(x+1))

domain

\frac{4 x - 8}{( x - 4 ) ( x + 1 )}

x < - 1 or - 1 < x < 4 or x > 4

Interval Notation

(- \infty, - 1) \cup (- 1, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 1

The function domain

x < - 1 or - 1 < x < 4 or x > 4

f (x) = 5 x - 12

\frac{2 x ( x - 1 ) ^{2}}{( x + 1 ) ^{3}}

f (x) = \frac{( x + 8 )}{( x - 4 )}

f (x) = \frac{1}{x - 2}

f (x) = \frac{1}{x - 1}

What is the domain of (4x-8)/((x-4)(x+1)) ?
The domain of (4x-8)/((x-4)(x+1)) is x<-1\lor-1<x<4\lor x>4