What is the critical 2x^3-3x^2+2 ?

The critical 2x^3-3x^2+2 is x=0,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical 2x^3-3x^2+2

critical points

2 x^{3} - 3 x^{2} + 2

x = 0, x = 1

Solution steps

2 x^{3} - 3 x^{2} + 2

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 1

Identify critical points not in

f (x)

domain

Domain of

2 x^{3} - 3 x^{2} + 2 : - \infty < x < \infty

All critical points are in domain

x = 0, x = 1

f (x) = - x^{2}

\frac{4 x}{x - 2}

f (x) = 3 (x - 3)

f (x) = x^{4} + 2 x^{2} + 2

- x + 7