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midpoint
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domain of f(x)=sqrt((x-1)^2)inflection f(x)=(-3)/(x^2+7)inverse of f(x)= 2/(5+x)line (-3,-2),(4,1)intercepts of f(x)=-x^2-6x-10
Frequently Asked Questions (FAQ)
What is the midpoint (-1,-4),(3,-5) ?
The midpoint (-1,-4),(3,-5) is (1,-9/2)