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Popular >

range of-2x^2+8x+24

Solution

range

- 2 x^{2} + 8 x + 24

Solution

f (x) \leq 32

+1

Interval Notation

(- \infty, 32]

Solution steps

Vertex of

- 2 x^{2} + 8 x + 24 :

Maximum

(2, 32)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 2,

Vertex

(x_{v}, y_{v}) = (2, 32)

f (x) \leq 32

Popular Examples

range of 2/(2-x)range

\frac{2}{2 - x}

inflection f(x)=5x^4-30x^2 inflection points

f (x) = 5 x^{4} - 30 x^{2}

inflection (x^2-4)/(x^2-1)inflection points

\frac{x ^{2} - 4}{x ^{2} - 1}

asymptotes of f(x)=-(x-1)/(x+3)asymptotes

f (x) = - \frac{x - 1}{x + 3}

simplify (7.7)(13.13)simplify

(7.7) (13.13)

Frequently Asked Questions (FAQ)

What is the range of-2x^2+8x+24 ?
The range of-2x^2+8x+24 is f(x)<= 32