What is the inverse of f(x)=4\sqrt[3]{x}+1 ?

The inverse of f(x)=4\sqrt[3]{x}+1 is (x^3)/(64)-(3x^2)/(64)+(3x)/(64)-1/64

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=4\sqrt[3]{x}+1

inverse

\frac{x ^{3}}{64} - \frac{3 x ^{2}}{64} + \frac{3 x}{64} - \frac{1}{64}

Solution steps

y = 4 3 x + 1

Replace

x

with

y

x = 4 3 y + 1

Solve for

y, x = 4 3 y + 1

\frac{x ^{3}}{64} - \frac{3 x ^{2}}{64} + \frac{3 x}{64} - \frac{1}{64}

What is the inverse of f(x)=4\sqrt[3]{x}+1 ?
The inverse of f(x)=4\sqrt[3]{x}+1 is (x^3)/(64)-(3x^2)/(64)+(3x)/(64)-1/64