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Popular >

distance (5,4),(4,7)

Solution

distance

(5, 4), (4, 7)

Solution

10

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(5, 4)

and

(4, 7)

is

= (4 - 5)^{2} + (7 - 4)^{2}

Simplify

= 10

Popular Examples

domain of f(x)=(x^2-2x+7)/(sqrt(4-x))domain

f (x) = \frac{x ^{2} - 2 x + 7}{4 - x}

range of f(x)=(11)/x range

f (x) = \frac{11}{x}

domain of f(x)=sin(7x)domain

f (x) = sin (7 x)

inflection f(x)=-2/(x+3)inflection points

f (x) = - \frac{2}{x + 3}

domain of |x|domain

∣ x ∣

Frequently Asked Questions (FAQ)

What is the distance (5,4),(4,7) ?
The distance (5,4),(4,7) is square root of 10