What is the domain of (x^2+8x-9)/(x^2+3x-4) ?

The domain of (x^2+8x-9)/(x^2+3x-4) is x 1

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domain of (x^2+8x-9)/(x^2+3x-4)

domain

\frac{x ^{2} + 8 x - 9}{x ^{2} + 3 x - 4}

x < - 4 or - 4 < x < 1 or x > 1

Interval Notation

(- \infty, - 4) \cup (- 4, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 4

The function domain

x < - 4 or - 4 < x < 1 or x > 1

f (x) = 3 ln (x) + 4

f (x) = - 4 x + 1

f (x) = 100 - 2 x

\frac{2 - x ^{2}}{1 + x ^{4}}

\frac{5 x}{x ^{2} - 3 x - 4}

What is the domain of (x^2+8x-9)/(x^2+3x-4) ?
The domain of (x^2+8x-9)/(x^2+3x-4) is x<-4\lor-4<x<1\lor x>1