What is the inverse of f(x)=160x-16x^2 ?

The inverse of f(x)=160x-16x^2 is -(-20+sqrt(-x+400))/4 ,(sqrt(-x+400)+20)/4

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inverse of f(x)=160x-16x^2

inverse

f (x) = 160 x - 16 x^{2}

- \frac{- 20 + - x + 400}{4}, \frac{- x + 400 + 20}{4}

Solution steps

y = 160 x - 16 x^{2}

Replace

x

with

y

x = 160 y - 16 y^{2}

Solve for

y, x = 160 y - 16 y^{2}

- \frac{- 20 + - x + 400}{4}, \frac{- x + 400 + 20}{4}

f (x) = \frac{4 x ^{5}}{x ^{6} - 3}

y = 1 - x

y = \frac{1}{2} x - 6

\frac{x - 3}{x ^{2} - 3 x - 18}

f (x) = \frac{2 x ^{2}}{x ^{2} - 1}

What is the inverse of f(x)=160x-16x^2 ?
The inverse of f(x)=160x-16x^2 is -(-20+sqrt(-x+400))/4 ,(sqrt(-x+400)+20)/4