What is the domain of f(x)=sqrt(2x-3) ?

The domain of f(x)=sqrt(2x-3) is x>= 3/2

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domain of f(x)=sqrt(2x-3)

domain

f (x) = 2 x - 3

x \geq \frac{3}{2}

Interval Notation

[\frac{3}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{3}{2}

The function domain

x \geq \frac{3}{2}

\frac{x + 4}{2 - x}

f (x) = \frac{120 + 4 x}{x}

f (x) = \frac{x + 5}{15 + x ^{2} - 64}

(- 5, 1), (7, 8)

f (x) = 4 - 6 x^{2}

What is the domain of f(x)=sqrt(2x-3) ?
The domain of f(x)=sqrt(2x-3) is x>= 3/2