What is the critical f(x)=2xe^{5x} ?

The critical f(x)=2xe^{5x} is x=-1/5

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critical f(x)=2xe^{5x}

critical points

f (x) = 2 x e^{5 x}

x = - \frac{1}{5}

Solution steps

2 x e^{5 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{5}

Identify critical points not in

f (x)

domain

Domain of

2 x e^{5 x} : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{5}

f (x) = \frac{5 x ^{2}}{x ^{2} - 4}

f (x) = 5 x + 2

f (x) = \frac{1}{2} cos (4 x)

\frac{2 x + 2}{x ^{2} - 1}