What is the inverse of f(x)=100(1-x/(40))^2 ?

The inverse of f(x)=100(1-x/(40))^2 is -4sqrt(x)+40,4sqrt(x)+40

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inverse of f(x)=100(1-x/(40))^2

inverse

f (x) = 100 (1 - \frac{x}{40})^{2}

- 4 x + 40, 4 x + 40

Solution steps

y = 100 (1 - \frac{x}{40})^{2}

Replace

x

with

y

x = 100 (1 - \frac{y}{40})^{2}

Solve for

y, x = 100 (1 - \frac{y}{40})^{2}

- 4 x + 40, 4 x + 40

f (x) = \frac{5}{x + 3}

f (x) = \frac{33 x}{4 x ^{5} - 3 x - 4}

(- 10, 7), (2, 5)

f (x) = \frac{3}{x - 2} + 9

5 cos (2 x + \frac{π}{2})

What is the inverse of f(x)=100(1-x/(40))^2 ?
The inverse of f(x)=100(1-x/(40))^2 is -4sqrt(x)+40,4sqrt(x)+40