What is the domain of f(x)=sqrt(x-7)+8 ?

The domain of f(x)=sqrt(x-7)+8 is x>= 7

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domain of f(x)=sqrt(x-7)+8

domain

f (x) = x - 7 + 8

x \geq 7

Interval Notation

[7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 7

The function domain

x \geq 7

- 7 x - 5 y = - 48

f (x) = \frac{2}{x ^{3} + 1}

f (x) = \frac{x + 2}{x ^{2} - 4}

- x^{2} + 2 x - 6

y = - \frac{2}{5} x + 8

What is the domain of f(x)=sqrt(x-7)+8 ?
The domain of f(x)=sqrt(x-7)+8 is x>= 7