en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Functions >

f(n)=4^{n+1}-2^{2n+1}

Solution

f (n) = 4^{n + 1} - 2^{2 n + 1}

Solution

Domain : - \infty < n < \infty

Range : f (x) > 0

Y Intercepts : (0, 2)

Asymptotes : None

Extreme Points : None

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (0, \infty)

Solution steps

Domain of

4^{n + 1} - 2^{2 n + 1} : - \infty < n < \infty

Range of

4^{n + 1} - 2^{2 n + 1} : f (x) > 0

Axis interception points of

4^{n + 1} - 2^{2 n + 1} :

Y Intercepts

: (0, 2)

Asymptotes of

4^{n + 1} - 2^{2 n + 1} :

None

Extreme Points of

4^{n + 1} - 2^{2 n + 1} :

None

Graph

Popular Examples

f(x)=(2x)/(e^x)

y= 1/(7t^3)-(t^{-4})/5+2ln(3)

f(x)=3x^2-5x^{(-3)}+6x^5

y=sec^2(t)-tan^2(t)

Frequently Asked Questions (FAQ)

What is the f(n)=4^{n+1}-2^{2n+1} ?
The f(n)=4^{n+1}-2^{2n+1} is