What is the domain of (sqrt(x))/(2x^2+x-1) ?

The domain of (sqrt(x))/(2x^2+x-1) is 0 1/2

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domain of (sqrt(x))/(2x^2+x-1)

domain

0 \leq x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{1}{2}, x = - 1

Combine real regions and undefined points for final function domain

0 \leq x < \frac{1}{2} or x > \frac{1}{2}

What is the domain of (sqrt(x))/(2x^2+x-1) ?
The domain of (sqrt(x))/(2x^2+x-1) is 0<= x< 1/2 \lor x> 1/2