What is the critical f(2)=xe^{-4x} ?

The critical f(2)=xe^{-4x} is x= 1/4

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critical f(2)=xe^{-4x}

critical points

f (2) = x e^{- 4 x}

x = \frac{1}{4}

Solution steps

x e^{- 4 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{4}

Identify critical points not in

f (x)

domain

Domain of

x e^{- 4 x} : - \infty < x < \infty

All critical points are in domain

x = \frac{1}{4}

y = - \frac{4}{3} x - 17, (4, - 12)

f (x) = e^{t}

2 x

3^{x + 3}

x^{4} + 2 x^{2}