What is the domain of f(x)=\sqrt[4]{x^2-2x+1} ?

The domain of f(x)=\sqrt[4]{x^2-2x+1} is -infinity <x<infinity

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domain of f(x)=\sqrt[4]{x^2-2x+1}

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

(- 6, 4), (- 8, 6)

cos (2 x + 5)

f (x) = 6 - 4 x

\frac{x}{2} - \frac{y}{3} = - 4

f (x) = - 4 x + 5

What is the domain of f(x)=\sqrt[4]{x^2-2x+1} ?
The domain of f(x)=\sqrt[4]{x^2-2x+1} is -infinity <x<infinity