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Popular Functions >

f(t)=(sqrt(t^2+9)-3)/(t^2)

Solution

f (t) = \frac{t ^{2} + 9 - 3}{t ^{2}}

Solution

Domain : t < 0 or t > 0

Range : 0 < f (t) < \frac{1}{6} or 0 < f (t) < \frac{1}{6}

Intercepts : None

Asymptotes : Horizontal y = 0

Extreme Points : None

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Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Range : (0, \frac{1}{6}) \cup (0, \frac{1}{6})

Solution steps

Domain of

\frac{t ^{2} + 9 - 3}{t ^{2}} : t < 0 or t > 0

Range of

\frac{t ^{2} + 9 - 3}{t ^{2}} : 0 < f (t) < \frac{1}{6} or 0 < f (t) < \frac{1}{6}

Axis interception points of

\frac{t ^{2} + 9 - 3}{t ^{2}} :

None

Asymptotes of

\frac{t ^{2} + 9 - 3}{t ^{2}} :

Horizontal

: y = 0

Extreme Points of

\frac{t ^{2} + 9 - 3}{t ^{2}} :

None

Graph

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Frequently Asked Questions (FAQ)

What is the f(t)=(sqrt(t^2+9)-3)/(t^2) ?
The f(t)=(sqrt(t^2+9)-3)/(t^2) is