What is the inverse of f(x)=(x+3)^2-1 ?

The inverse of f(x)=(x+3)^2-1 is sqrt(x+1)-3,-sqrt(x+1)-3

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inverse of f(x)=(x+3)^2-1

inverse

f (x) = (x + 3)^{2} - 1

x + 1 - 3, - x + 1 - 3

Solution steps

y = (x + 3)^{2} - 1

Replace

x

with

y

x = (y + 3)^{2} - 1

Solve for

y, x = (y + 3)^{2} - 1

x + 1 - 3, - x + 1 - 3

y = \frac{3}{4} - 2 - x

f (x) = 2 x^{2} + x + 2, - 1 \leq x \leq 3

f (x) = sin (x), 0 \leq x < π^{2}

\frac{- x ^{2} - x + 6}{x ^{2} + 3 x - 4}

f (x) = 2 x - 1 + 3

What is the inverse of f(x)=(x+3)^2-1 ?
The inverse of f(x)=(x+3)^2-1 is sqrt(x+1)-3,-sqrt(x+1)-3