What is the inverse of f(x)=(9x-9)/(8x+1) ?

The inverse of f(x)=(9x-9)/(8x+1) is (-9-x)/(8x-9)

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inverse of f(x)=(9x-9)/(8x+1)

inverse

f (x) = \frac{9 x - 9}{8 x + 1}

\frac{- 9 - x}{8 x - 9}

Solution steps

y = \frac{9 x - 9}{8 x + 1}

Replace

x

with

y

x = \frac{9 y - 9}{8 y + 1}

Solve for

y, x = \frac{9 y - 9}{8 y + 1}

\frac{- 9 - x}{8 x - 9}

6 x - 3

f (x) = 3 + 5 + x

f (x) = x^{3} - 3 x + 1, - 3 \leq x \leq 3

23

y = 3 x - 3

What is the inverse of f(x)=(9x-9)/(8x+1) ?
The inverse of f(x)=(9x-9)/(8x+1) is (-9-x)/(8x-9)