What is the range of f(x)=3sin(x/2) ?

The range of f(x)=3sin(x/2) is -3<= f(x)<= 3

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range of f(x)=3sin(x/2)

range

f (x) = 3 sin (\frac{x}{2})

- 3 \leq f (x) \leq 3

Interval Notation

[- 3, 3]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (\frac{x}{2}) \leq 1

- 1 \leq sin (\frac{x}{2}) \leq 1

Multiply the edges of the range by:

3

- 3 \leq 3 sin (\frac{x}{2}) \leq 3

Therefore the range is

- 3 \leq f (x) \leq 3

- \frac{1}{z} \frac{1}{z - 1}

f (x) = - x - 10

\frac{9}{5} c + 32

f (x) = \frac{4 x ^{2} - 4}{x + 1}

(- 6, 12), (2, - 20)

What is the range of f(x)=3sin(x/2) ?
The range of f(x)=3sin(x/2) is -3<= f(x)<= 3