What is the d/(dθ)(4sin(θ)) ?

The d/(dθ)(4sin(θ)) is 4cos(θ)

What is the first d/(dθ)(4sin(θ)) ?

The first d/(dθ)(4sin(θ)) is 4cos(θ)

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\frac{d}{d θ} (4 sin (θ))

4 cos (θ)

Solution steps

\frac{d}{d θ} (4 sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= 4 cos (θ)

x^{2} + 3

12 + 4 y = - 4 x

x^{3} - 9 x^{2} + 15 x + 8

m = - 2, (1, 7)

f (x) = \frac{6}{x ^{2}}