What is the inverse of f(x)=(7-8t)^{7/2} ?

The inverse of f(x)=(7-8t)^{7/2} is -(t^{2/7}-7)/8

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inverse of f(x)=(7-8t)^{7/2}

inverse

f (x) = (7 - 8 t)^{\frac{7}{2}}

- \frac{t ^{\frac{2}{7}} - 7}{8}

Solution steps

x = (7 - 8 t)^{\frac{7}{2}}

Replace

t

with

x

t = (7 - 8 x)^{\frac{7}{2}}

Solve for

x, t = (7 - 8 x)^{\frac{7}{2}}

- \frac{t ^{\frac{2}{7}} - 7}{8}

f (x) = \frac{x ^{2} ( x + 4 )}{( 7 x ^{2} - 3 )}

y = - 3 x^{2} + 30 x - 2

5 cos (π x - 2) + 5

f (x) = \frac{32}{x + 3}

y = cos (x - \frac{π}{6})

What is the inverse of f(x)=(7-8t)^{7/2} ?
The inverse of f(x)=(7-8t)^{7/2} is -(t^{2/7}-7)/8