What is the inverse of f(x)=3x^2+9 ?

The inverse of f(x)=3x^2+9 is sqrt((x-9)/3),-sqrt((x-9)/3)

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inverse of f(x)=3x^2+9

inverse

f (x) = 3 x^{2} + 9

\frac{x - 9}{3}, - \frac{x - 9}{3}

Solution steps

y = 3 x^{2} + 9

Replace

x

with

y

x = 3 y^{2} + 9

Solve for

y, x = 3 y^{2} + 9

\frac{x - 9}{3}, - \frac{x - 9}{3}

f (x) = \frac{3}{2 x + 4}

4 \cdot (\frac{2}{3})^{x} + 1

f (x) = \frac{1}{4} x

x - 3 x^{\frac{1}{3}}

f (x) = lo g_{3} (x)

What is the inverse of f(x)=3x^2+9 ?
The inverse of f(x)=3x^2+9 is sqrt((x-9)/3),-sqrt((x-9)/3)