What is the asymptotes of y=sec(x+1) ?

The asymptotes of y=sec(x+1) is Vertical: x=(3pi)/2-1+2pin,x= pi/2-1+2pin

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asymptotes of y=sec(x+1)

asymptotes

y = sec (x + 1)

Vertical : x = \frac{3 π}{2} - 1 + 2 πn, x = \frac{π}{2} - 1 + 2 πn

Solution steps

Vertical asymptotes of

sec (x + 1) : x = \frac{3 π}{2} - 1 + 2 πn, x = \frac{π}{2} - 1 + 2 πn

Horizontal Asymptotes of

sec (x + 1) :

None

Slant Asymptotes of

sec (x + 1) :

None

Vertical : x = \frac{3 π}{2} - 1 + 2 πn, x = \frac{π}{2} - 1 + 2 πn

- \frac{2}{5} x^{3}

(52, 73), (2, - 3)

\frac{x + 3}{x ^{2} - 2 x - 8}

(- 1.2) y = x + 4

What is the asymptotes of y=sec(x+1) ?
The asymptotes of y=sec(x+1) is Vertical: x=(3pi)/2-1+2pin,x= pi/2-1+2pin