What is the line (0, pi/2),(pi,-pi/2) ?

The line (0, pi/2),(pi,-pi/2) is y=-x+pi/2

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line (0, pi/2),(pi,-pi/2)

line

(0, \frac{π}{2}), (π, - \frac{π}{2})

y = - x + \frac{π}{2}

Solution steps

Find the line

y = mx + b

passing through

(0, \frac{π}{2})

(π, - \frac{π}{2})

Compute the slope

(0, \frac{π}{2}), (π, - \frac{π}{2}) : m = - 1

Compute the

y

intercept:

b = \frac{π}{2}

Construct the line equation

y = mx + b

where

m = - 1

and

b = \frac{π}{2}

y = - x + \frac{π}{2}

ln (cos (x)) tan (x) d x

f (x) = - 2 x

(7, 4), (- 3, - 3)

8

What is the line (0, pi/2),(pi,-pi/2) ?
The line (0, pi/2),(pi,-pi/2) is y=-x+pi/2