What is the domain of f(x)=sqrt(2-x)+sqrt(x^2-1) ?

The domain of f(x)=sqrt(2-x)+sqrt(x^2-1) is x<=-1\lor 1<= x<= 2

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domain of f(x)=sqrt(2-x)+sqrt(x^2-1)

domain

f (x) = 2 - x + x^{2} - 1

x \leq - 1 or 1 \leq x \leq 2

Interval Notation

(- \infty, - 1] \cup [1, 2]

Solution steps

Find non-negative values for radicals:

x \leq - 1 or 1 \leq x \leq 2

The function domain

x \leq - 1 or 1 \leq x \leq 2

f (x) = - 2 x^{3} - 6

- \frac{5}{2 t ^{\frac{3}{2}}}

e^{3 x}

2 x^{3} - 13

f (x) = \frac{4 x ^{2}}{x ^{2} + 1}

What is the domain of f(x)=sqrt(2-x)+sqrt(x^2-1) ?
The domain of f(x)=sqrt(2-x)+sqrt(x^2-1) is x<=-1\lor 1<= x<= 2