What is the inverse of f(x)=(x+2)^{1/5}+3 ?

The inverse of f(x)=(x+2)^{1/5}+3 is x^5-15x^4+90x^3-270x^2+405x-245

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inverse of f(x)=(x+2)^{1/5}+3

inverse

f (x) = (x + 2)^{\frac{1}{5}} + 3

x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 245

Solution steps

y = (x + 2)^{\frac{1}{5}} + 3

Replace

x

with

y

x = (y + 2)^{\frac{1}{5}} + 3

Solve for

y, x = (y + 2)^{\frac{1}{5}} + 3

x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 245

f (x) = e^{x - 3} + 4

x^{2} - 4

f (x) = \frac{x ^{2} - x - 56}{2 x - 16}

f (x) = (x - 3)^{\frac{2}{3}}

cos (x - \frac{π}{2})

What is the inverse of f(x)=(x+2)^{1/5}+3 ?
The inverse of f(x)=(x+2)^{1/5}+3 is x^5-15x^4+90x^3-270x^2+405x-245