What is the inverse of f(x)=(\sqrt[5]{x}+2)^7 ?

The inverse of f(x)=(\sqrt[5]{x}+2)^7 is x^{5/7}-10x^{4/7}+40x^{3/7}-80x^{2/7}+80\sqrt[7]{x}-32

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=(\sqrt[5]{x}+2)^7

inverse

x^{\frac{5}{7}} - 10 x^{\frac{4}{7}} + 40 x^{\frac{3}{7}} - 80 x^{\frac{2}{7}} + 80 7 x - 32

Solution steps

y = (5 x + 2)^{7}

Replace

x

with

y

x = (5 y + 2)^{7}

Solve for

y, x = (5 y + 2)^{7}

x^{\frac{5}{7}} - 10 x^{\frac{4}{7}} + 40 x^{\frac{3}{7}} - 80 x^{\frac{2}{7}} + 80 7 x - 32

What is the inverse of f(x)=(\sqrt[5]{x}+2)^7 ?
The inverse of f(x)=(\sqrt[5]{x}+2)^7 is x^{5/7}-10x^{4/7}+40x^{3/7}-80x^{2/7}+80\sqrt[7]{x}-32