What is the inverse of f(x)=((x-3))/((x+7)) ?

The inverse of f(x)=((x-3))/((x+7)) is (-3-7x)/(x-1)

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inverse of f(x)=((x-3))/((x+7))

inverse

f (x) = \frac{( x - 3 )}{( x + 7 )}

\frac{- 3 - 7 x}{x - 1}

Solution steps

y = \frac{x - 3}{x + 7}

Replace

x

with

y

x = \frac{y - 3}{y + 7}

Solve for

y, x = \frac{y - 3}{y + 7}

\frac{- 3 - 7 x}{x - 1}

\frac{sin ( 3 y ) cot ( 5 y )}{y cot ( 4 y )}

f (x) = 1 - (\frac{3}{x ^{2} - 1})

f (x) = 2 x + 3

f (x) = sin^{2} (x)

What is the inverse of f(x)=((x-3))/((x+7)) ?
The inverse of f(x)=((x-3))/((x+7)) is (-3-7x)/(x-1)