What is the domain of f(x)=(x+2)/(24-sqrt(x^2-49)) ?

The domain of f(x)=(x+2)/(24-sqrt(x^2-49)) is x 25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x+2)/(24-sqrt(x^2-49))

domain

f (x) = \frac{x + 2}{24 - x ^{2} - 49}

x < - 25 or - 25 < x \leq - 7 or 7 \leq x < 25 or x > 25

Interval Notation

(- \infty, - 25) \cup (- 25, - 7] \cup [7, 25) \cup (25, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 7 or x \geq 7

Find undefined (singularity) points:

x = 25, x = - 25

Combine real regions and undefined points for final function domain

x < - 25 or - 25 < x \leq - 7 or 7 \leq x < 25 or x > 25

x + \frac{12}{x}

y = x^{2} + 1

\frac{1}{x}

f (x) = 2 - x^{3}

f (x) = x^{3} + 2 x - 1

What is the domain of f(x)=(x+2)/(24-sqrt(x^2-49)) ?
The domain of f(x)=(x+2)/(24-sqrt(x^2-49)) is x<-25\lor-25<x<=-7\lor 7<= x<25\lor x>25