What is the inverse of y=-25x^2+15x+120 ?

The inverse of y=-25x^2+15x+120 is -(-3+sqrt(-4x+489))/(10),(sqrt(-4x+489)+3)/(10)

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inverse of y=-25x^2+15x+120

inverse

y = - 25 x^{2} + 15 x + 120

- \frac{- 3 + - 4 x + 489}{10}, \frac{- 4 x + 489 + 3}{10}

Solution steps

y = - 25 x^{2} + 15 x + 120

Replace

x

with

y

x = - 25 y^{2} + 15 y + 120

Solve for

y, x = - 25 y^{2} + 15 y + 120

- \frac{- 3 + - 4 x + 489}{10}, \frac{- 4 x + 489 + 3}{10}

(4, - 4), (6, 4)

x^{2} + x

y = - 1

1 - x

What is the inverse of y=-25x^2+15x+120 ?
The inverse of y=-25x^2+15x+120 is -(-3+sqrt(-4x+489))/(10),(sqrt(-4x+489)+3)/(10)