What is the domain of f(x)=(sqrt(3+x))/(6-x) ?

The domain of f(x)=(sqrt(3+x))/(6-x) is -3 6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(sqrt(3+x))/(6-x)

domain

f (x) = \frac{3 + x}{6 - x}

- 3 \leq x < 6 or x > 6

Interval Notation

[- 3, 6) \cup (6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = 6

Combine real regions and undefined points for final function domain

- 3 \leq x < 6 or x > 6

f (x) = (\frac{1}{2}) \cdot 6^{x}

x + 4 - 2

f (x) = x + 1

(x + 7)^{3} - 2

f (x) = \frac{x + 3}{x ^{2} - x - 12}

What is the domain of f(x)=(sqrt(3+x))/(6-x) ?
The domain of f(x)=(sqrt(3+x))/(6-x) is -3<= x<6\lor x>6