What is the domain of G(t)=-(13)/((4+t)^2) ?

The domain of G(t)=-(13)/((4+t)^2) is t -4

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domain of G(t)=-(13)/((4+t)^2)

domain

G (t) = - \frac{13}{( 4 + t ) ^{2}}

t < - 4 or t > - 4

Interval Notation

(- \infty, - 4) \cup (- 4, \infty)

Solution steps

Find undefined (singularity) points:

t = - 4

The function domain

t < - 4 or t > - 4

(- 5, - 1), (4, 2)

4 x - 5 y = - 10

f (x) = 4^{x}

\frac{x ^{2}}{x + 3}

f (x) = \frac{- 4}{x + 2}

What is the domain of G(t)=-(13)/((4+t)^2) ?
The domain of G(t)=-(13)/((4+t)^2) is t<-4\lor t>-4