What is the domain of f(x)=\sqrt[4]{x-9} ?

The domain of f(x)=\sqrt[4]{x-9} is x>= 9

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domain of f(x)=\sqrt[4]{x-9}

domain

x \geq 9

Interval Notation

[9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 9

The function domain

x \geq 9

f (x) = (4 - 10 x)^{\frac{5}{2}}

f (x) = \frac{( x ^{3} - x )}{( 1 + x ^{2} )}

f (x) = \frac{x ( x - 1 ) ( x - 2 ) ( x - 3 )}{24}

f (x) = \frac{3}{x - 4}

f (x) = 45 - 9 x

What is the domain of f(x)=\sqrt[4]{x-9} ?
The domain of f(x)=\sqrt[4]{x-9} is x>= 9