What is the f(x)= 5/(3-x)+(sqrt(25-x^2-9))/(3-|x-2|) ?

The f(x)= 5/(3-x)+(sqrt(25-x^2-9))/(3-|x-2|) is

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f(x)= 5/(3-x)+(sqrt(25-x^2-9))/(3-|x-2|)

f (x) = \frac{5}{3 - x} + \frac{25 - x ^{2} - 9}{3 - ∣ x - 2 ∣}

Domain : - 4 \leq x < - 1 or - 1 < x < 3 or 3 < x \leq 4

Range : f (x) \leq \frac{5}{7} or f (x) \geq 4.43120 \dots

X Intercepts : (- 3.50586 \dots, 0), Y Intercepts : (0, \frac{17}{3})

Asymptotes : Vertical x = - 1, x = 3

Extreme Points : Maximum (- 4, \frac{5}{7}), Minimum (0.93063 \dots, 4.43120 \dots), Maximum (3.95171 \dots, - 4.66257 \dots), Minimum (4, - 5)

Interval Notation

Domain : [- 4, - 1) \cup (- 1, 3) \cup (3, 4]

Range : (- \infty, \frac{5}{7}] \cup [4.43120 \dots, \infty)

Solution steps

Domain of

\frac{5}{3 - x} + \frac{25 - x ^{2} - 9}{3 - ∣ x - 2 ∣} : - 4 \leq x < - 1 or - 1 < x < 3 or 3 < x \leq 4

Range of

\frac{5}{3 - x} + \frac{25 - x ^{2} - 9}{3 - ∣ x - 2 ∣} : f (x) \leq \frac{5}{7} or f (x) \geq 4.43120 \dots

Axis interception points of

\frac{5}{3 - x} + \frac{25 - x ^{2} - 9}{3 - ∣ x - 2 ∣} :

X Intercepts

: (- 3.50586 \dots, 0),

Y Intercepts

: (0, \frac{17}{3})

Asymptotes of

\frac{5}{3 - x} + \frac{25 - x ^{2} - 9}{3 - ∣ x - 2 ∣} :

Vertical

: x = - 1, x = 3

Extreme Points of

\frac{5}{3 - x} + \frac{25 - x ^{2} - 9}{3 - ∣ x - 2 ∣} :

Maximum

(- 4, \frac{5}{7}),

Minimum

(0.93063 \dots, 4.43120 \dots),

Maximum

(3.95171 \dots, - 4.66257 \dots),

Minimum

(4, - 5)

What is the f(x)= 5/(3-x)+(sqrt(25-x^2-9))/(3-|x-2|) ?
The f(x)= 5/(3-x)+(sqrt(25-x^2-9))/(3-|x-2|) is