What is the derivative of ln(ln(\sqrt[3]{x^9})) ?

The derivative of ln(ln(\sqrt[3]{x^9})) is 1/(xln(x))

What is the first derivative of ln(ln(\sqrt[3]{x^9})) ?

The first derivative of ln(ln(\sqrt[3]{x^9})) is 1/(xln(x))

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\frac{1}{x ln ( x )}

Solution steps

Apply the chain rule:

Simplify

= \frac{1}{x ln ( x )}

\frac{\partial}{\partial y} (x sin (y) + y cos (x))

\int \frac{x ^{2} - 4}{x} d x

\frac{d}{d x} (x^{2} 2 x - 3)

x^{2} y^{^{'}} + \frac{4}{3} x y = - 4 cos (3 x) y^{- \frac{1}{2}}

x \to 1 + lim (\frac{1}{x ^{2} - 1})

What is the derivative of ln(ln(\sqrt[3]{x^9})) ?
The derivative of ln(ln(\sqrt[3]{x^9})) is 1/(xln(x))
What is the first derivative of ln(ln(\sqrt[3]{x^9})) ?
The first derivative of ln(ln(\sqrt[3]{x^9})) is 1/(xln(x))