What is laplacetransform 10sin(3t) ?

The answer to laplacetransform 10sin(3t) is (30)/(s^2+9)

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laplacetransform 10sin(3t)

laplace transform

10 sin (3 t)

\frac{30}{s ^{2} + 9}

Solution steps

L {10 sin (3 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 10 L {sin (3 t)}

L {sin (3 t)} : \frac{3}{s ^{2} + 9}

= 10 \cdot \frac{3}{s ^{2} + 9}

Refine

10 \frac{3}{s ^{2} + 9} : \frac{30}{s ^{2} + 9}

= \frac{30}{s ^{2} + 9}

\int (x + π) sin (n x) d x

y^{'} = 0.0014 y (1700 - y)

4 cos^{2} (2 t)

\frac{3 x + 7}{4 x - 5}

n = 0 \sum \infty 37.06

What is laplacetransform 10sin(3t) ?
The answer to laplacetransform 10sin(3t) is (30)/(s^2+9)