What is the derivative of y=5x+ln(3x) ?

The derivative of y=5x+ln(3x) is 5+1/x

What is the first derivative of y=5x+ln(3x) ?

The first derivative of y=5x+ln(3x) is 5+1/x

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derivative of

y = 5 x + ln (3 x)

5 + \frac{1}{x}

Solution steps

\frac{d}{d x} (5 x + ln (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x) + \frac{d}{d x} (ln (3 x))

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (ln (3 x)) = \frac{1}{x}

= 5 + \frac{1}{x}

f^{^{'}} (x) = 4 x + 2

\int x^{2} x^{2} + 3 d x

\frac{\partial}{\partial x} (\frac{5 x}{( 3 + y )})

y^{^{''}} - 2 y^{^{'}} = 2 x

f (x) = x^{- \frac{2}{5}} + x^{\frac{2}{5}}

What is the derivative of y=5x+ln(3x) ?
The derivative of y=5x+ln(3x) is 5+1/x
What is the first derivative of y=5x+ln(3x) ?
The first derivative of y=5x+ln(3x) is 5+1/x