What is the derivative of f(x)=x^{-2/5}+x^{2/5} ?

The derivative of f(x)=x^{-2/5}+x^{2/5} is -2/(5x^{7/5)}+2/(5x^{3/5)}

What is the first derivative of f(x)=x^{-2/5}+x^{2/5} ?

The first derivative of f(x)=x^{-2/5}+x^{2/5} is -2/(5x^{7/5)}+2/(5x^{3/5)}

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derivative of

f (x) = x^{- \frac{2}{5}} + x^{\frac{2}{5}}

- \frac{2}{5 x ^{\frac{7}{5}}} + \frac{2}{5 x ^{\frac{3}{5}}}

Solution steps

\frac{d}{d x} (x^{- \frac{2}{5}} + x^{\frac{2}{5}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{- \frac{2}{5}}) + \frac{d}{d x} (x^{\frac{2}{5}})

\frac{d}{d x} (x^{- \frac{2}{5}}) = - \frac{2}{5 x ^{\frac{7}{5}}}

\frac{d}{d x} (x^{\frac{2}{5}}) = \frac{2}{5 x ^{\frac{3}{5}}}

= - \frac{2}{5 x ^{\frac{7}{5}}} + \frac{2}{5 x ^{\frac{3}{5}}}

\frac{\partial}{\partial y} (\frac{y ^{2}}{1 + x ^{2}})

\int \frac{x - 2}{x ^{2} - 7 x + 12} d x

\frac{d y}{d x} = \frac{x ( 1 + y ^{2} )}{4 y}

\frac{d}{d x} (\frac{x}{2} + \frac{3}{2} + \frac{4}{x + 1})

x (x - 4) y^{^{'}} + y = 0

What is the derivative of f(x)=x^{-2/5}+x^{2/5} ?
The derivative of f(x)=x^{-2/5}+x^{2/5} is -2/(5x^{7/5)}+2/(5x^{3/5)}
What is the first derivative of f(x)=x^{-2/5}+x^{2/5} ?
The first derivative of f(x)=x^{-2/5}+x^{2/5} is -2/(5x^{7/5)}+2/(5x^{3/5)}