What is the solution for x(dy)/(dx)=y^2+y ?

The solution for x(dy)/(dx)=y^2+y is y=(e^{c_{1}}x)/(1-e^{c_{1)}x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x(dy)/(dx)=y^2+y

x \frac{d y}{d x} = y^{2} + y

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

Solution steps

x \frac{d y}{d x} = y^{2} + y

Solve separable ODE:

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

\int_{0}^{4} x - 1 d x

y = 5 - x^{2}

\int (6 x + 5) 3 x^{2} + 5 x d x

t \to 0 lim (\frac{4 t ^{2} + 3 t + 2}{t ^{3} + 2 t - 6})

f (x) = - x^{2} + 3 x - 1

What is the solution for x(dy)/(dx)=y^2+y ?
The solution for x(dy)/(dx)=y^2+y is y=(e^{c_{1}}x)/(1-e^{c_{1)}x}