What is the limit as t approaches 0 of (4t^2+3t+2)/(t^3+2t-6) ?

The limit as t approaches 0 of (4t^2+3t+2)/(t^3+2t-6) is -1/3

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limit as t approaches 0 of (4t^2+3t+2)/(t^3+2t-6)

t \to 0 lim (\frac{4 t ^{2} + 3 t + 2}{t ^{3} + 2 t - 6})

- \frac{1}{3}

Decimal Notation

- 0.33333 \dots

Solution steps

t \to 0 lim (\frac{4 t ^{2} + 3 t + 2}{t ^{3} + 2 t - 6})

Plug in the value

t = 0

= \frac{4 \cdot 0 ^{2} + 3 \cdot 0 + 2}{0 ^{3} + 2 \cdot 0 - 6}

Simplify

\frac{4 \cdot 0 ^{2} + 3 \cdot 0 + 2}{0 ^{3} + 2 \cdot 0 - 6} : - \frac{1}{3}

= - \frac{1}{3}

f (x) = - x^{2} + 3 x - 1

\int \frac{( e ^{2 x} )}{e ^{4 x} + 4} d x

\int \frac{1}{8 - 2 x - x ^{2}} d x

\frac{d}{d x} (\frac{3}{2})

\frac{\partial}{\partial x} (3 e)

What is the limit as t approaches 0 of (4t^2+3t+2)/(t^3+2t-6) ?
The limit as t approaches 0 of (4t^2+3t+2)/(t^3+2t-6) is -1/3