What is the integral from 1 to 36 of 1/(2x) ?

The integral from 1 to 36 of 1/(2x) is ln(6)

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integral from 1 to 36 of 1/(2x)

\int_{1}^{36} \frac{1}{2 x} d x

ln (6)

Decimal Notation

1.79175 \dots

Solution steps

\int_{1}^{36} \frac{1}{2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{1}^{36} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= \frac{1}{2} [ln ∣ x ∣]_{1}^{36}

Compute the boundaries:

2 ln (6)

= \frac{1}{2} \cdot 2 ln (6)

Simplify

= ln (6)

x \to - 5 lim (3 x + 2)

\int x^{3} 81 + x^{2} d x

\frac{\partial}{\partial x} (e^{- \frac{x}{2 y}})

x \to 0 lim (\frac{4}{14 + x})

y = \frac{( x - 2 )}{y + 3}

What is the integral from 1 to 36 of 1/(2x) ?
The integral from 1 to 36 of 1/(2x) is ln(6)