What is the derivative of y=((x-2))/(y+3) ?

The derivative of y=((x-2))/(y+3) is 1/(y+3)

What is the first derivative of y=((x-2))/(y+3) ?

The first derivative of y=((x-2))/(y+3) is 1/(y+3)

Popular >

derivative of

y = \frac{( x - 2 )}{y + 3}

\frac{1}{y + 3}

Solution steps

\frac{d}{d x} (\frac{x - 2}{y + 3})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{y + 3} \frac{d}{d x} (x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{y + 3} (\frac{d x}{d x} - \frac{d}{d x} (2))

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= \frac{1}{y + 3} (1 - 0)

Simplify

= \frac{1}{y + 3}

f (x) = e^{x^{2} + 1}

x \to 0 lim (1 + \frac{1}{4 x ^{2}})

\int \frac{x - 2}{( x + 1 )} d x

\int tan^{7} (\frac{x}{2}) sec^{2} (\frac{x}{2}) d x

\int 1.8 t d t

What is the derivative of y=((x-2))/(y+3) ?
The derivative of y=((x-2))/(y+3) is 1/(y+3)
What is the first derivative of y=((x-2))/(y+3) ?
The first derivative of y=((x-2))/(y+3) is 1/(y+3)