What is the derivative of 9x^7+3x^5-6x^6-2x^4 ?

The derivative of 9x^7+3x^5-6x^6-2x^4 is 63x^6+15x^4-36x^5-8x^3

What is the first derivative of 9x^7+3x^5-6x^6-2x^4 ?

The first derivative of 9x^7+3x^5-6x^6-2x^4 is 63x^6+15x^4-36x^5-8x^3

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\frac{d}{d x} (9 x^{7} + 3 x^{5} - 6 x^{6} - 2 x^{4})

63 x^{6} + 15 x^{4} - 36 x^{5} - 8 x^{3}

Solution steps

\frac{d}{d x} (9 x^{7} + 3 x^{5} - 6 x^{6} - 2 x^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x^{7}) + \frac{d}{d x} (3 x^{5}) - \frac{d}{d x} (6 x^{6}) - \frac{d}{d x} (2 x^{4})

\frac{d}{d x} (9 x^{7}) = 63 x^{6}

\frac{d}{d x} (3 x^{5}) = 15 x^{4}

\frac{d}{d x} (6 x^{6}) = 36 x^{5}

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

= 63 x^{6} + 15 x^{4} - 36 x^{5} - 8 x^{3}

\frac{d}{d x} (5 x^{2} + 7 x - 6)

10 x \cdot e^{x}

\int_{0}^{1} 1.5 x^{2} d x

\frac{\partial}{\partial s} (2 s^{2} t^{2})

\frac{d}{d x} (\frac{x}{11} - \frac{11}{x})

What is the derivative of 9x^7+3x^5-6x^6-2x^4 ?
The derivative of 9x^7+3x^5-6x^6-2x^4 is 63x^6+15x^4-36x^5-8x^3
What is the first derivative of 9x^7+3x^5-6x^6-2x^4 ?
The first derivative of 9x^7+3x^5-6x^6-2x^4 is 63x^6+15x^4-36x^5-8x^3