What is the integral from 0 to 1 of 1.5x^2 ?

The integral from 0 to 1 of 1.5x^2 is 0.49999…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of 1.5x^2

\int_{0}^{1} 1.5 x^{2} d x

0.49999 \dots

Solution steps

\int_{0}^{1} 1.5 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 1.5 \cdot \int_{0}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{1}

= 1.5 [\frac{x ^{3}}{3}]_{0}^{1}

Simplify

= 1.5 [0.33333 \dots x^{3}]_{0}^{1}

Compute the boundaries:

0.33333 \dots

= 1.5 \cdot 0.33333 \dots

Simplify

= 0.49999 \dots

\frac{\partial}{\partial s} (2 s^{2} t^{2})

\frac{d}{d x} (\frac{x}{11} - \frac{11}{x})

\frac{d}{d x} (2 x + \frac{1}{ln ( x ^{2} + e ) + 1} - 4)

\frac{x}{4} arcsin (x)

What is the integral from 0 to 1 of 1.5x^2 ?
The integral from 0 to 1 of 1.5x^2 is 0.49999…