What is the derivative of-2x+1/x ?

The derivative of-2x+1/x is -2-1/(x^2)

What is the first derivative of-2x+1/x ?

The first derivative of-2x+1/x is -2-1/(x^2)

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\frac{d}{d x} (- 2 x + \frac{1}{x})

- 2 - \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (- 2 x + \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x) + \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= - 2 - \frac{1}{x ^{2}}

\int (5 x^{2} + 5 x - 4) d x

x cos (x^{2})

\frac{d}{d x} (\frac{x + 6}{5 x ^{2} e ^{x}})

f (x) = - cos (x)

x \to 16 lim (x - 164)

What is the derivative of-2x+1/x ?
The derivative of-2x+1/x is -2-1/(x^2)
What is the first derivative of-2x+1/x ?
The first derivative of-2x+1/x is -2-1/(x^2)