What is the integral of (5x^2+5x-4) ?

The integral of (5x^2+5x-4) is (5x^3)/3+(5x^2)/2-4x+C

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integral of (5x^2+5x-4)

\int (5 x^{2} + 5 x - 4) d x

\frac{5 x ^{3}}{3} + \frac{5 x ^{2}}{2} - 4 x + C

Solution steps

\int 5 x^{2} + 5 x - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 x^{2} d x + \int 5 x d x - \int 4 d x

\int 5 x^{2} d x = \frac{5 x ^{3}}{3}

\int 5 x d x = \frac{5 x ^{2}}{2}

\int 4 d x = 4 x

= \frac{5 x ^{3}}{3} + \frac{5 x ^{2}}{2} - 4 x

Add a constant to the solution

= \frac{5 x ^{3}}{3} + \frac{5 x ^{2}}{2} - 4 x + C

x cos (x^{2})

\frac{d}{d x} (\frac{x + 6}{5 x ^{2} e ^{x}})

f (x) = - cos (x)

x \to 16 lim (x - 164)

\frac{\partial}{\partial x} (arctan (x^{2} + y^{2}))

What is the integral of (5x^2+5x-4) ?
The integral of (5x^2+5x-4) is (5x^3)/3+(5x^2)/2-4x+C